Consider the Fibonacci-like recurrence a_n = ± a_(n - 1) ± a_(n - 2), where a_0 = 0, a_1 = 1, and each sign is chosen independently and at random with probability 1/2. Surprisingly, Viswanath showed that lim_(n->∞) ( left bracketing bar a_n right bracketing bar )^(1/n) = 1.13199... (OEIS A078416) with probability one. This constant is sometimes known as Viswanath's constant.
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